5x^2-56x+126=0

Solution for 5x^2-56x+126=0 equation:

5x^2-56x+126=0

a = 5; b = -56; c = +126;
Δ = b2-4ac
Δ = -562-4·5·126
Δ = 616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{616}=\sqrt{4*154}=\sqrt{4}*\sqrt{154}=2\sqrt{154}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-2\sqrt{154}}{2*5}=\frac{56-2\sqrt{154}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+2\sqrt{154}}{2*5}=\frac{56+2\sqrt{154}}{10}
$